(0,5x^2)+2x-2=2

Solution for (0,5x^2)+2x-2=2 equation:

(0.5x^2)+2x-2=2

We move all terms to the left:

(0.5x^2)+2x-2-(2)=0

We add all the numbers together, and all the variables

2x+(0.5x^2)-4=0

We get rid of parentheses

0.5x^2+2x-4=0

a = 0.5; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·0.5·(-4)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3}}{2*0.5}=\frac{-2-2\sqrt{3}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3}}{2*0.5}=\frac{-2+2\sqrt{3}}{1}
$